# CAP 14b Las mareas en una tierra plana.

Hi, this is Albert Tothosap today we are going to finish the chapter of the tides and try to go a little further. As we saw … whoever saw it as gravity is not a plausible explanation for the tides that we have let’s see how they work and understand what we can we will review the issue of the tides and get deep good as we see the tide the solar tide has two maximum points on the side of the sun, we read that it has a major attraction and on the opposite side to the sun there is another high tide created by the sun we read that it has a minor attraction we see again and remember, denied centrifugal accelerations It tells us that the explanation is the gravitational difference or gravity gradient between those two zones well let’s calculate it to the previous calculation we had we have to add the diameter of the planet now we add the 12740 km and we get a difference very small we turn it into kilopondios there isn’t even a difference of one gram we still have 599 grams the difference is one tenth of a gram per ton it doesn’t seem like such a big difference let’s see let’s try to understand from the point of view of the moon, what the moon explains to us Here explains the same, the effect of gravitational attraction, even in the drawing, if you look, the arrow is wrong says that there is a part that is attracted to the moon with those 3.3 gf and on the opposite side of the earth, draw the arrow with gravity working backwards let’s see, this… and talks about the gravitational gradient again, but we have already seen that the gravitational gradient is… minuscule however this is true both solar and lunar tides are on opposite sides of the planet at the same time. maybe the answer is in the centrifugal force let’s calculate the centrifugal force of that ton around the sun the angular velocity would be in this case, revolutions per day 1 divided by 365 we already know the radius thousand kilos of water decimals and let’s see, 608 gf per ton Here we begin to understand things We go back to the article of the tide and go down to this beautiful photo where it explains the interaction between the tides remember that solar tide lasts 12 hours the moon tide is 12 h 25 min 10 sec so sometimes they get together and sometimes they separate we see in this drawing the sun, and how the solar tide is always with its direct axis towards the sun and when the moon is aligned the tides add up on both full moon and new moon and when it’s on a waning moon or rising the tides are separated goob why deny centrifugal force?, the result obtained is 599 gr per ton of gravitational attraction with a tenth of a gram of difference the gravitational gradient does not seem to matter and we got 608 gf 608 gf centrifugal force that we should ignore why should we ignore it? because if we don’t do it, we would find a semi-explanation for the model of the sun, but when you try to apply it to the moon there is no centrifugal force to compensate in this crossing of forces, the greatest is the centrifugal force produced by the earth, remember that it was 3.4 grams per kilo! not per ton! 3,4 kilos per ton and… there is no explanation there is no explanation for the moon, with a gravitational attraction of 3.3 gf per ton and a derisory gravitational gradient, to do this This is not understood, I can not understand it in any way let’s understand it easily with this drawing the surprise comes, when all this, so complicated, with so many failures we represent it in a 2-dimensional drawing in a flat earth so it’s all much easier Here we see how the tide of the sun is spinning It’s how it has to be, on both sides of the planet the moon tide also fits everything we know about tides is fulfilled no need for strange forces or complex explanations the only thing is electromagnetic traction